Received 16 June 2016; accepted 11 July 2016; published 14 July 2016
1. Introduction
Let F, G and H be graphs. A G-decomposition of F is a partition of the edge set of F into copies of G. If F has a G-decomposition, we say that F is G-decomposable. Let be a family of subgraphs of a graph G. An L-decomposition of G is an edge-disjoint decomposition of G into positive integer copies of, where. If G has an L-decomposition, we say that G is L-decomposable.
For positive integers m and n, denotes the complete bipartite graph with parts of sizes m and n. A complete bipartite graph is balanced if. A k-cycle, denoted by, is a cycle of length k. A k-star, denoted by, is the complete bipartite graph. A k-path, denoted by, is a path with k edges. For a graph G and an integer, we use to denote the multigraph obtained from G by replacing each edge e by edges each of which has the same ends as e.
Decompositions of graphs into k-stars have also attracted a fair share of interest (see [1] - [3] ). Articles of - decompositions of interest include [4] [5] . Decompositions of some families of graphs into k-cycles have been a popular topic of research in graph theory (see [6] [7] for surveys of this topic). The study of -decom- position was introduced by Abueida and Daven in [8] . Abueida and Daven [9] investigated the problem of -decomposition of the complete graph. Abueida and O’Neil [10] settled the existence problem for -decomposition of the complete multigraph for. In [11] , Priyadharsini and Muth- usamy gave necessary and sufficient conditions for the existence of a -factorization of where. Furthermore, Shyu [12] investigated the problem of decomposing into paths and stars with k edges, giving a necessary and sufficient condition for. In [13] , Shyu considered the existence of a decomposition of into paths and cycles with k edges, giving a necessary and sufficient condition for. Shyu [14] investigated the problem of decomposing into cycles and stars with k edges, settling the case. Recently, Lee [15] [16] established necessary and sufficient conditions for the existence of a -decomposition of a complete bipartite graph and -decomposition of a balanced complete bi- partite graph. Lin and Jou [17] investigated the problems of the -decomposition of the balanced complete bipartite graph. It is natural to consider the problem of the -decomposition of the balanced complete bipartite multigraph for. In this paper, the necessary and sufficient conditions for the existence of such decomposition are given.
2. Preliminaries
Let G be a graph. The degree of a vertex x of G, denoted by, is the number of edges incident with x. The vertex of degree k in is the center of. For and, we use and to denote the subgraph of G induced by A and the subgraph of G obtained by deleting B, respectively.
When are graphs, not necessarily disjoint, we write or for the graph with vertex set and edge set. When the edge sets are disjoint,
expresses the decomposition of G into. is the short notation for the union of n copies of disjoint graphs isomorphic to G. Let H be a subgraph of with vertex set and edge set, and let r be a nonnegative integer. We use to denote the graph with vertex set and edge set where the subscripts of b are taken modulo n. For any vertex x of a digraph G, the outdegree (respectively, indegree) of x is the number of arcs incident from (respectively, to) x. A multistar is a star with multiple edges allowed. We use to denote a multistar with k edges. Let G be a multigraph. The edge-multiplicity of an edge in G is the number of edges joining the vertices of the edge. The multiplicity of G, denoted by, is the maximum edge- multiplicity of G.
Lemma 1. ( [3] ) For integers m and n with, the graph has an -decomposition if and only if and
Lemma 2. ( [18] ) Suppose that. Then is -decomposable.
Let denote the edge ab in the s-th copy of for.
Lemma 3. If k is an even integer with, then there exist edge-disjoint 2k-cycles in.
Proof. A decomposition of into 2k-cycles is given by the following cycles:, where, and. □
Note that can be decomposed into two copies of k-paths:
and, that
is, can be decomposed into copies of k-paths.
Lemma 4. ( [4] ) There exists a -decomposition of if and only if, and one of the following (see Table 1) cases occurs.
Lemma 5. ( [19] ) For positive integers m, n and k, the graph has a -decomposition if and only if and k are even, , , and.
Table 1. The conditions of a -decomposition of.
3. Main Results
With the results ( [17] ) of the -decomposition of the balanced complete bipartite graph, it is assumed that in the sequel. In this section, we will prove the following result.
Main Theorem. Let k and n be positive integers. The graph has a -decomposition if and only if k is even, and.
We first give necessary conditions for a -decomposition of.
Lemma 6. If has a -decomposition, then k is even, and.
Proof. Since bipartite graphs contain no odd cycle, k is even. In addition, the minimum length of a cycle and the maximum size of a star in are 4 and n, respectively, we have. Finally, the size of each member in the decomposition is k and; thus. □
Throughout this paper, let denote the bipartition of, where and. We now show that the necessary conditions are also sufficient. The proof is divided into cases, , and, which are treated in Lemmas 7, 8, and 9, respectively.
Lemma 7. For an even integer, then has a -decomposition.
Proof. Note that. By Lemmas 1 and 4, has a -decomposition and a -decomposition. In addition, by Lemma 5, has a -decomposition. Hence has a -decomposition. □
Lemma 8. Let k be a positive even integer and let n be a positive integer with. If is divisible by k, then has a -decomposition.
Proof. Let. From the assumption, we have. Let. Since, we have, which implies that t is a positive integer. The proof is divided into two cases according to the values of t.
Case 1..
Let, ,
and.
Clearly. Note that G is isomorphic to, is isomorphic to, is isomorphic to and F is isomorphic to, which can be decomposed into copies of by Lemmas 1 and 2. In the following, we will show that can be decomposed into copies of, one copy of and copies of.
Let, where and. Define a subgraph W of G as follows:
and the subscripts of b are taken modulo k. Note that for t is even, and
for t is odd, this assures us that there are enough edges for W. Note that a can be decomposed into 2 copies of. In addition, for t is even as well as for t is odd, it follows that W can be decomposed into t copies of. Since, we
interchange two edges in and in, then we obtain a new cycle
. Hence can be decomposed into
copies of and one copy of.
Let be the graph obtained from G by deleting the edges in W. For the case of t is even, we have that
The other case of t is odd, we have that
Let for. Then for t is even, and for t is odd
with the center at.
In the following, we will show that can be decomposed into r copies of with centers in, and into k copies of with centers in for t is even as well as k/2 copies
of with centers in and copies of with centers in for t
is odd, that is, there exists an orientation of such that
(1)
where, and for t is even
(2)
where, and for t is odd
(3)
We first consider the edges oriented outward from. If t is even, then the edges
are all oriented outward from where. If t is odd, for
, the edges and
are all oriented outward from, where the subscripts of b are taken modulo r in the set. In both of the cases the subscripts of b are taken modulo r in the set of numbers. Since for t is even, and for t is odd, this assures us that there are enough edges for the above orientation. Finally, the edges which are not oriented yet are all oriented from to.
From the construction of the orientation, it is easy to see that (2) and (3) are satisfied, and for all, we have
(4)
So, we only need to check (1).
Since for, it follows from (4) that
for. Note that t is even, , and t is odd,
Thus,
Therefore for. This proves (1). Hence, there exists the required decomposition of. Let be the star with center at in for. Then is an. Since, by Lemma 2, we obtain that can be decomposed into copies of for.
Let be the -multistar with center at in for. Let
for. Then is decomposed into, ,
and each. It follows that. Since, by Lemma 2, we obtain that can be decomposed into copies of for. Recall that , we have that is -decomposable.
Case 2..
Let, ,
and.
Then. By similar arguments as in the proof of Case 1, we have that can be decomposed into one copy of and copies of. On the other hand, by Lemma 5, has a -decomposition. Hence has a -decomposition. □
Lemma 9. Let k be a positive even integer and let n be a positive integer with. If is divisible by k, then has a -decomposition.
Proof. Let where q and r are integers with. From the assumption of, we have. Note that
Trivially, , and are multiples of k. Thus
from the assumption that is divisible by k. By Lemmas 1 and 2, , and have -decomposition.
In the case of, by Lemma 7, we obtain that has a -decomposition. In addition, by Lemma 8, has a -decomposition for. Hence there exists a -de composition of. □
Now we are ready for the main result. It is obtained by combining Lemmas 6, 7, 8 and 9.
Theorem 1. Let k and n be positive integers. The graph has a -decomposition if and only if k is even, and.
Remark. Let m and n be positwe integers with. Since bipartite graphs contain no odd cycle, k is even. In addition, the minimum length of a cycle and the maximum size of a star in are 4 and m, respectively, we have. Moreover, each k-cycle in uses vertices of each partite set, which implies
that. Finally, the size of each member in the decomposition is k and, thus
. Hence the obvious necessary conditions for the graph to have a -de composition are: 1) k is even, 2), and 3). It is natural to ask whether they are sufficient.
Acknowledgements
The authors are grateful to the referees for the helpful comments.