On the Monoid of All Order Preserving Full Contractions with a Fixed Set

Abstract

In this paper, we consider the monoid FixOCT( [ n ],D ) of all order-preserving full contraction mappings that fix a subset say D of a finite n -element chain { 1,2,,n } . We characterize regularity, Green’s relations, and starred Green’s relations, and show that this monoid is left adequate. Furthermore, we determine the cardinality of FixOCT( [ n ],D ) , the ranks of its two-sided ideals, and demonstrate that the ranks of the two-sided ideals and their corresponding Rees quotients are equal. Moreover, we deduce the rank of the monoid FixOCT( [ n ],D ) .

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Zubairu, M. and Lawan, Z. (2025) On the Monoid of All Order Preserving Full Contractions with a Fixed Set. Open Journal of Discrete Mathematics, 15, 55-71. doi: 10.4236/ojdm.2025.153004.

1. Introduction and Preliminaries

Denote [ n ] to be a finite n -chain { 1,2,,n } . A map that has both its domain and range subsets of [ n ] is said to be a transformation of the set [ n ] . A transformation that has its domain subset of [ n ] is said to be partial. The collection of all partial transformations on [ n ] is known as the semigroup of partial transformations and is usually denoted by . A partial transformation whose domain is equal to [ n ] is said to be a full (or total) transformation. The collection of all full transformations on [ n ] is known as the semigroup of full transformations, which is usually denoted by T n . A map α T n is said to be order preserving if (for all x,y[ n ] ) xy implies xαyα . The collection of all order preserving full transformations on [ n ] is known as the semigroup of order preserving full transformations and is usually denoted by O n . The algebraic, combinatorial and the rank properties of the semigroup O n have been extensively studied over the years, see for example [1]-[11].

Let D be a nonempty subset of [ n ] . Denote by FixT( [ n ],D ) to be the collection of all α T n that fix elements of D that is, FixT( [ n ],D )={ α T n :aα=a,forallaD } . The set FixT( [ n ],D ) is known as the semigroup of transformations with a fixed set under the usual composition of functions. This semigroup first appeared in [12], where its algebraic, combinatorial and rank properties were investigated. In particular, the authors in [12] investigated its Green’s relations, ideals, isomorphisms and rank properties. Later, Chaiya et al. [13] characterized all the maximal subsemigroups of FixT( [ n ],D ) , while the natural partial order on FixT( [ n ],D ) was investigated in [14]. There are various semigroups of transformations with fixed sets that have been studied by various authors, see for example [15] [16]. For basic concepts in semigroup theory, we refer the reader to the books [17]-[19].

A map α T n is said to be an isometry if for all x,y[ n ] , | xαyα |=| xy | ; and is said to be a contraction if for all x,y[ n ] , | xαyα || xy | . Let

C T n ={ α T n :( forallx,y[ n ] )| xαyα || xy | } (1)

be the semigroup of all of full contractions on [ n ] and

OC T n ={ αC T n :( forallx,y[ n ] )xyxαyα } (2)

be the semigroup of all order-preserving full contractions of [ n ] . A general study of these semigroups was initiated in 2013 by Umar and Al-Kharousi [20], in a research proposal to the Research Council of Oman. In this proposal, notations for these semigroups and their various subesmigroups were given. We are adopting the same notations for these semigroups in this paper.

The combinatorial properties of the semigroup OC T n have been investigated by Adeshola and Umar [21], where they showed that the order of OC T n is ( n+1 ) 2 n2 . Ali et al. [22] characterized both the regular elements and Green’s relations of the semigroups C T n and OC T n . Moreover, they proved that the collection of all regular elements of OC T n (denoted by RegOC T n ) is a subsemigroup, and also showed that the Rees quotient of the two-sided ideal of RegOC T n is an inverse semigroup. Recently, Toker [23] investigated the rank properties of OC T n .

For a nonempty subset D of [ n ] , let

FixOCT( [ n ],D )={ αOC T n :dα=d,foralldD } (3)

be the monoid of all order preserving full contraction mappings with a fixed set D . It is straightforward to show that FixOCT( [ n ],D ) is a subsemigroup of OC T n . Moreover, it is evident that id [ n ] FixOCT( [ n ],D ) (where id [ n ] denotes the identity map on [ n ] ) for every nonempty subset D[ n ] . Hence, FixOCT( [ n ],D ) is a monoid. Notice that if { 1,n }D , then

FixOCT( [ n ],D )={ i d [ n ] } 1 (i.e., FixOCT( [ n ],D ) is the trivial group). Thus, for the rest of the paper, we will only consider case where D does not contain { 1,n } . Furthermore, let a=maxD and b=minD , and let D ¯ ={ x[ n ]:axb } . Then, we shall refer to D ¯ as closure of D .

Now, for 1rpn1 , let

L( nr,p )={ αFixOCT( [ n ],D ):r| Imα |p } (4)

be the two-sided ideal of FixOCT( [ n ],D ) , and let

J p * ={ αFixOCT( [ n ],D ):| Imα |=p } (5)

be the collection of elements in FixOCT( [ n ],D ) of height p . Evidently, J r * J r+1 * J p * =L( nr,p ) . Additionally, let

F( n,p )=| J p * |. (6)

Furthermore, for p>1 , let

D n ( p )= L( nr,p )/ L( nr,p1 ) (7)

be the Rees quotient semigroup of L( nr,p ) , where the product of two elements α and β in D n ( p ) is zero if their product has height less than p , otherwise it is αβ .

The monoid FixOCT( [ n ],D ) does not seem to have been studied in the literature. In this paper, we investigate the algebraic, combinatorial and rank properties of this monoid. Section 1 of this paper contains the definitions of basic terms. In Section 2, we give a characterization of regular elements as well as a necessary and sufficient condition for the monoid FixOCT( [ n ],D ) to be regular. Moreover, we characterize all the Green’s relations and starred Green’s relations on the monoid FixOCT( [ n ],D ) . In Section 3, we compute the cardinality and the rank of FixOCT( [ n ],D ) . Finally, we study certain isomorphism properties on the monoid.

In line with [17], every transformation αFixOCT( [ n ],D ) can be written as

α=( A 1 A p x 1 x p )( 1pn ), (8)

where A i ( 1ip ) (also referred to as blocks) are equivalence classes under the relation kerα={ ( x,y )[ n ]×[ n ]:xα=yα } . The collection of all the equivalence classes of the relation kerα , is the partition of [ n ] usually denoted by Kerα , i.e., Kerα={ A 1 ,, A p } ( pn ). A subset X of [ n ] is said to be convex if xy ( x,yX ) and if there exists z[ n ] such that x<z<y implies zX . Let P be a partition of [ n ] , then P is called convex if any element E of P is convex. Moreover, a partition P is said to be ordered if for all A i , A j P , A i < A j if and only if a<b for all a A i and b A j . Notice that if P is an ordered partition then its necessarily convex. A subset T α of [ n ] is said to be a transversal of the partition Kerα if | T α |=p , and | A i T α |=1 ( 1ip ) .

For any transformation α , we shall denote Imα , h( α ) , F( α )={ x[ n ]:xα=x } and f( α ) to mean the image set of α , | Imα | , the set of fixed points of α and the number of the fixed points of α (i.e., | F( α ) | ), respectively. For α,βFixOCT( [ n ],D ) , we shall write the composition of α and β as x( αβ )=( ( x )α )β for all x[ n ] .

Let S be a semigroup, a subset A of S is said to be a generating set of S , if every element of S can be written as a product of elements of A . If A generates S , we simply write A =S . The rank of a semigroup S is defined and denoted by

rank( S )=min{ | A |:AS, A =S }.

An element aS is said to be an idempotent if a 2 =a . The collection of all idempotents of S is usually denoted by E( S ) . It is well known that an element α (where α is expressed as in (8)) in any transformation semigroup is an idempotent if and only if A i is stationary in the sense that x i A i for all 1ip .

Before we begin our discussion, the following remark is worth noticing:

Remark 1.1.

1) For n3 and any nonempty subset D of [ n ] of order 1, FixOCT( [ n ],D )OC T n . Evidently, for all 1in2 and D={ i } , the element

( { 1,,i } { i+1,,n } i+1 i+2 )

is in OC T n , but not in FixOCT( [ n ],D ) .

Moreover, if i=n1 or i=n , the element α=( { 1,,n1 } n n2 n1 )OC T n , but does not fix n1 and n , so αFixOCT( [ n ],D ) .

2) For n4 and any nonempty subset D of [ n ] of order r2 , FixOCT( [ n ],D )OC T n .

Notice that for any D[ n ] with minD=i and maxD=i+r1 , the element

( { 1,,i1 } { i,i+1,,i+r1 } { i+r,,n } i1 i i+1 )OC T n ,

but not in FixOCT( [ n ],D ) since the element i+1 is an element of D and is not a fixed point, and so, FixOCT( [ n ],D )OC T n .

The following Lemma from [21] is needed in our subsequent discussion.

Lemma 1.2. ([21] Lemma 1.2) Let αC T n and let | Imα |=p . Then, Imα is convex.

We now have the following lemma.

Lemma 1.3. If αFixOCT( [ n ],D ) . Then, aα=a for all a D ¯ . In other words, if αFixOCT( [ n ],D ) , then α must fix D ¯ .

Proof. Let αFixOCT( [ n ],D ) and let a=minD and b=maxD . Now, suppose by way of contradiction that there exists c D ¯ such that cαc . Notice that a<c<b . Then, by the order preserving property of α , we must have aα<cα<bα , i.e., a<cα<b . Now since cαc , then either c>cα or cα>c . Thus, we consider the two cases separately.

Case 1. Suppose cα>c , i.e., a<cα<b . Then, | aαcα |=| acα |>| ac | , contradicting the fact that α is a contraction.

Case 2. Suppose cα<c i.e., a<cα<c<b . Then, | bαcα |=| bcα |>| bc | , contradicting the fact that α is a contraction. The result now follows. □

The elements in the monoid FixOCT( [ n ],D ) have a general expression as in the lemma below.

Lemma 1.4. Let minD=a+i and maxD=a+r+i1 for some 1ip and for some 0anp , so that D ¯ ={ a+j:ijr+i1 } , where r=| D ¯ | . Then, every αFixOCT( [ n ],D ) of height p can be expressed as

α=( A 1 A i1 { min A i ,,a+i } a+i+1 a+i+r2 { a+i+r1,,max A i+r1 } A i+r A p a+1 a+i1 a+i a+i+1 a+i+r2 a+i+r1 a+i+r a+p ). (9)

Proof. Let αFixOCT( [ n ],D ) be of height 1pn . Then, as in (8), α can be expressed as

( A 1 A p x 1 x p ).

Now since α is a contraction, then by Lemma 1.2, Imα is convex i.e., Imα={ a+1,,a+p } for some 0anp . Thus, α can be expressed as

( A 1 A p a+1 a+p ).

Now since αFixOCT( [ n ],D ) , then by Lemma 1.3, α must fix D ¯ . Notice that D ¯ ={ a+j:ijr+i1 } for some 1ip , and so, ( a+j )α=a+j for all ijr+i1 , where a+i=max A i =min D ¯ and a+r+i1=min A i+r1 =max D ¯ . Thus, α can be expressed as

( A 1 A i1 { min A i ,,a+i } a+i+1 a+i+r2 { a+i+r1,,max A i+r1 } A i+r A p a+1 a+i1 a+i a+i+1 a+i+r2 a+i+r1 a+i+r a+p ),

as required. □

We note the following remark.

Remark 1.5. It is worth noting that the block A k ( 1ki1 and i+rkp ) can be empty.

For the purpose of illustrations, take n=9 , i.e., [ 9 ]={ 1,,9 } and D={ 4,6 } . Let αFixOCT( [ 9 ],{ 4,6 } ) be

( 1 { 2,3 } 4 5 { 6,7 } { 8,9 } 2 3 4 5 6 7 ) .

Notice that r=| D ¯ |=3 and p=6 . Moreover, the position of the first element in D is in A 3 , i.e., i=3 , and so a=1 . The block containing the maximum element of D ¯ is at the position A i+r1 = A 3+31 = A 5 . Thus, the blocks containing the elements of D ¯ are A 3 ={ 4 } , A 4 ={ 5 } and A 5 ={ 6,7 } . Other blocks are A 1 ={ 1 } , A 2 ={ 2,3 } and A 6 ={ 8,9 } .

Now, consider

α=( { 1,2,3,4 } 5 { 6,7 } { 8,9 } 4 5 6 7 )FixOCT( [ 9 ],{ 4,6 } ) .

Clearly, A 1 is the block containing the minimum element 4 while A 3 contain the maximum element 6 in D ¯ , and so the blocks that contains the elements of D ¯ are A 1 ={ 1,2,3,4 } , A 2 ={ 5 } and A 3 ={ 6,7 } . It is worth noting that there is no any block before A 1 and there is one block after A 3 , i.e., the block A 4 ={ 8,9 } .

Moreover, consider

α=( 1 { 2,3 } 4 5 { 6,7,8,9 } 2 3 4 5 6 )FixOCT( [ 9 ],{ 4,6 } ).

Notice that the blocks containing the elements in D ¯ are A 3 ={ 4 } , A 4 ={ 5 } and A 5 ={ 6,7,8,9 } . While other blocks are A 1 ={ 1 } and A 2 ={ 2,3 } . Obviously, there are two blocks before A 3 and there is no block after A 5 .

Furthermore, consider αFixOCT( [ 9 ],{ 4,6 } ) as

( { 1,2,3,4 } 5 { 6,7,8,9 } 4 5 6 ) .

A 1 ={ 1,2,3,4 } is the block containing the minimum element of D ¯ while A 3 contain the maximum element. Thus, there is not any block before A 1 and after A 3 .

The following is worth remarking.

Remark 1.6. Clearly if D ¯ ={ a+j:ijr+i1 } , then A j ={ a j } ( i+1jr+i2 ) .

We now present the following lemma.

Lemma 1.7. For any D[ n ] , FixOCT( [ n ],D )=FixOCT( [ n ], D ¯ ) .

Proof. Let αFixOCT( [ n ],D ) . Then, by Lemma 1.3, α fix D ¯ , and so αFixOCT( [ n ], D ¯ ) .

On the other hand, if αFixOCT( [ n ], D ¯ ) , then α fix D (since D D ¯ ) and therefore αFixOCT( [ n ],D ) . Thus, the result follows.

2. Regularity and Green’s Relations on FixOCT( [ n ],D )

Let S be a semigroup without identity element and S 1 be a monoid. The five equivalences classes on S known as Green’s relations were first introduced by J. A. Green in 1951. The primary aim of defining these relations is to study the structure of a semigroup S . These relations are defined as follows. For a,bS , ab if and only if S 1 a= S 1 b ; ab if and only if a S 1 =b S 1 ; aJb if and if S 1 a S 1 = S 1 b S 1 . The relation = , while the relation D is a join of the relations and , i.e., D= . For more details on the properties of Green’s relations, we refer the reader to [3] [18] [19].

An element a in a semigroup S is regular if there exists bS such that a=aba . If every element of S is regular, then S is called a regular semigroup. If a semigroup with idempotent elements is not regular, then there is need to investigate the regular elements, so as to identify the -classes and -classes that contain idempotents. The semigroup FixOCT( [ n ],D ) is not regular in general, but can be regular for certain D[ n ] , as we are going to discuss below, in this section.

The Greens relations for the semigroup C T n and some of its subsemigroups have been investigated in [22]. Here, we also characterize these relations on the semigroup FixOCT( [ n ],D ) . Throughout this section, we will consider 1| D |<[ n ] .

We begin our investigation by first noting the following well-known lemmas:

Lemma 2.1. ([22], Corollary 44) Let α,βOC T n be as expressed as in (8). Then, ( α,β ) if and only Imα=Imβ and α ker _ β .

Lemma 2.2. ([22], Corollary 45) Let α,βOC T n be expressed as in (8). Then, ( α,β ) if and only kerα=kerβ .

Lemma 2.3. ([21], Lemma 1.1) Let αC T n be such that f( α )=m . Then, F( α )={ i,i+1,,i+m1 } . Equivalently, F( α ) is convex.

Lemma 2.4. If α,βFixOCT( [ n ],D ) such that kerα=kerβ , then α=β .

Proof. Let α,βFixOCT( [ n ],D ) such that kerα=kerβ . Suppose α is expressed as in (9), i.e.,

α=( A 1 A i1 { min A i ,,a+i } a+i+1 a+i+r2 { a+i+r1,,max A i+r1 } A i+r A p a+1 a+i1 a+i a+i+1 a+i+r2 a+i+r1 a+i+r a+p )

and let

β=( A 1 A i1 { min A i ,,a+i } a+i+1 a+i+r2 { a+i+r1,,max A i+r1 } A i+r A p b+1 b+i1 a+i a+i+1 a+i+r2 a+i+r1 a+i+r b+p ).

Thus, by Lemma 1.2, Imβ is convex, and therefore a+i=b+i1+1 . This implies a=b , and as such α=β , as required. □

From this point onward, we shall let α and β be of the form:

α=( A 1 A i1 { min A i ,,a+i } a+i+1 a+i+r2 { a+i+r1,,max A i+r1 } A i+r A p a+1 a+i1 a+i a+i+1 a+i+r2 a+i+r1 a+i+r a+p ) (10)

and

β=( B 1 B i1 { min B i ,,a+i } a+i+1 a+i+r2 { a+i+r1,,max B i+r1 } B i+r B p a+1 a+i1 a+i a+i+1 a+i+r2 a+i+r1 a+i+r a+p ). (11)

Next, we characterize the Green’s relations on FixOCT( [ n ],D ) .

Theorem 2.5. Let α,βFixOCT( [ n ],D ) be expressed as in and (11), respectively. Then,

1) ( α,β ) if and only α=β ;

2) ( α,β ) if and only α=β .

Proof. 1) Let D ¯ ={ a+i,,a+i+r1 } , | D ¯ |=r and α,βFixOCT( [ n ],D ) be as expressed in (10) and (11) such that ( α,β ) . Since α,βOC T n , then by Corollary 2.1, Imα=Imβ and α ker _ β . This means that there is an isometry from A j to B j for all j{ 1,,i,i+r1,,p } . Notice that 1 A 1 , 1 B 1 and since there is an isometry from A 1 to B 1 and from B 1 to A 1 , then A 1 = B 1 . Inductively, we see that A j = B j , for all j{ 1,,i,i+r1,,p } . Hence, α=β .

Conversely, suppose α=β . Now let γ= id n . Clearly, id n FixOCT( [ n ],D ) , α=γβ and β=γα .

2) The result follows directly from Lemma 2.2 and Lemma 2.4.

Consequently, we have the following Corollaries.

Corollary 2.6. On the monoid FixOCT( [ n ],D ) , ==J=D= .

As a consequence of the above Corollary, we deduce the following characterization of Green’s relations on the semigroup S{ D n ( p ),L( nr,p ) } .

Theorem 2.7. Let S{ D n ( p ),L( nr,p ) } . Then, S is J -trivial and therefore, the semigroup S is non-regular.

Next, we deduce the characterization of the regular element in FixOCT( [ n ],D ) below:

Corollary 2.8. Let αFixOCT( [ n ],D ) be as expressed in Equation (10). Then, α is regular if and only if α is an idempotent.

Proof. The result follows from the fact that FixOCT( [ n ],D ) is an -trivial semigroup. □

Now, as a consequence of Corollary 2.6, we readily have the following result.

Theorem 2.9. Every H α ( αE( FixOCT( [ n ],D ) ) ) is a maximal subgroup of FixOCT( [ n ],D ) and is isomorphic to the trivial group 1 .

The next thing is to investigate when the whole semigroup FixOCT( [ n ],D ) is regular. First, we note the following.

Remark 2.10. 1) Obviously if n=1 , then OCT( [ 1 ],D )={ ( 1 1 ) } , which is a regular semigroup.

2) Moreover, if n=2 , then FixOCT( [ 2 ],{ 1 } )={ ( { 1,2 } 1 ),( 1 2 1 2 ) } and FixOCT( [ 2 ],{ 2 } )={ ( { 1,2 } 2 ),( 1 2 2 2 ) } . Evidently, the semigroup S{ FixOCT( [ 2 ],{ 1 } ),FixOCT( [ 2 ],{ 2 } ) } is regular, since every element in S is a regular idempotent element.

3) However, if n=3 , then D is in one of the following forms { 1 },{ 2 },{ 3 },{ 1,2 } or { 2,3 } . Thus,

FixOCT( [ 3 ],{ 1 } )={ ( { 1,2,3 } 1 ),( { 1,2 } 3 1 2 ),( 1 { 2,3 } 1 2 ),( 1 2 3 1 2 3 ) }

and

FixOCT( [ 3 ],{ 3 } )={ ( { 1,2,3 } 3 ),( { 1,2 } 3 2 3 ),( 1 { 2,3 } 2 3 ),( 1 2 3 1 2 3 ) }

are non-regular monoids due to the fact that the elements ( { 1,2 } 3 1 2 )FixOCT( [ 3 ],{ 1 } ) and ( 1 { 2,3 } 2 3 )FixOCT( [ 3 ],{ 3 } ) are not regular. Furthermore, the monoids FixOCT( [ 3 ],{ 2 } )={ ( { 1,2,3 } 2 ),( { 1,2 } 3 2 3 ),( 1 { 2,3 } 1 2 ),( 1 2 3 1 2 3 ) } , FixOCT( [ 3 ],{ 1,2 } )={ ( 1 { 2,3 } 1 2 ),( 1 2 3 1 2 3 ) } and FixOCT( [ 3 ],{ 2,3 } )={ ( { 1,2 } 3 2 3 ),( 1 2 3 1 2 3 ) } are regular.

Further, we investigate when the whole semigroup FixOCT( [ n ],D ) is regular for n4 , in the Theorem below.

Theorem 2.11. For n4 , the monoid FixOCT( [ n ],D ) is regular if and only if D ¯ { { 2,,n1 },{ 1,,n1 },{ 2,,n },{ n } } .

Proof. FixOCT( [ n ],D ) is regular if and only if every element in FixOCT( [ n ],D ) is regular if and only if every element in FixOCT( [ n ],D ) is an idempotent (by Corollary 2.8) if and only if the kernel class of every element in FixOCT( [ n ],D ) has a transversal T which is equal to D ¯ if and only if D ¯ ={ 2,,n1 } or D ¯ ={ 1,,n1 } or D ¯ ={ 2,,n } or D ¯ ={ n } .

Thus, we have the following remark:

Remark 2.12. For n4 , the monoid FixOCT( [ n ],D ) is not regular if and only if minD3 or maxDn2 .

Starred Green’s Relations

There are five starred Green’s equivalences defined on a semigroup S , namely , , D , and J . In a semigroup S and for a,bS , ( a,b ) if and only if ( a,b ) in some over semigroup of S say T . The relation ( a,b ) is defined dually. We shall use the notation ( a,b )( S ) to mean ( a,b ) in S and similarly, ( a,b ) ( S ) to mean ( a,b ) in S . The relations and have the following characterizations as in [24]:

( S )={ ( a,b ):( forallx,y S 1 )ax=aybx=by } (12)

and

( S )={ ( a,b ):( forallx,y S 1 )xa=yaxb=yb }. (13)

The join of the relations and is D while their intersection is . For basic definitions of starred Green’s relations, we refer the reader to [24] [25]. If a semigroup S is not regular, then there is a need to characterize its starred Green’s relations in order to investigate the class to which it belongs. Now, in this section, we shall consider D[ n ] which does not belong to the set { { 1,n1 },{ 2,n1 },{ 2,n },{ 1,n } } .

We now record the following result from [19].

Lemma 2.13. ([19], Ex. 2.6 (16)) Let α,β T n . Then

1) ( α,β ) if and only if Imα=Imβ ;

2) ( α,β ) if and only if kerα=kerβ ;

3) ( α,β )D if and only if | Imα |=| Imβ | ;

4) D=J .

Now, we give the characterization of the relations and on the monoid FixOCT( [ n ],D ) in the theorems below.

Theorem 2.14. Let α,βFixOCT( [ n ],D ) be expressed as in (10) and (11), respectively. Then, ( α,β ) if and only if Imα=Imβ .

Proof. Suppose ( α,β ) . Now define γ:[ n ][ n ] by

xγ={ a+1, if1xa+1; x, ifa+1<x<a+p; a+p, ifa+p<xn.

Then, obviously γFixOCT( [ n ],D ) and one can easily verify that αγ=α id [ n ] if and only if βγ=β id [ n ] (by (12)). Obviously,

Imβ{ a+1,,a+p }=Imα.

Thus, ImαImβ . Similarly, one can show that ImβImα . Therefore, Imα=Imβ .

Conversely, if Imα=Imβ , then by Lemma 2.13, ( α,β )( T n ) . Thus, by definition it follows that ( α,β ) A ( FixOCT( [ n ],D ) ) . □

Theorem 2.15. On the monoid FixOCT( [ n ],D ) , = .

Proof. The result follows from definition and Theorem 2.5-2). □

Theorem 2.16. Let α,βFixOCT( [ n ], D ) . Then, ( α,β ) D if and only if Imα=Imβ .

Proof. Suppose ( α,β ) D . This means that there exists γFixOCT( [ n ],D ) such that ( α,γ ) and ( γ,β ) . Then, by Theorem 2.14, Imα=Imγ and by Theorem 2.15, γ=β . Thus, Imα=Imβ , as required.

Conversely, if Imα=Imβ . Then, since D is reflexive, it follows that ( α,β ) D . □

Now, we have the following remark:

Remark 2.17. On the semigroup S{ D n ( p ),L( nr,p ) } ,

1) = ;

2) D = .

A semigroup S is said to be a left abundant (resp., right abundant) if both the -class (resp., -class) contains an idempotent and S is said to be abundant if both -class and -class contains an idempotent [24]. A semigroup S is said to be left quasi-adequate (resp., right quasi-adequate) if it is left abundant (resp., right abundant) and its set of idempotent elements forms a subsemigroup, and it is quasi-adequate if it is both left and right quasi-adequate [24].

We now present the following results.

Theorem 2.18. The monoid FixOCT( [ n ],D ) is left abundant.

Proof. Let D ¯ ={ a+i,,a+i+r1 } and αFixOCT( [ n ],D ) . Denote α to be the -class of αFixOCT( [ n ],D ) . Now either D ¯ [ n ]\ D ¯ or [ n ]\ D ¯ D ¯ or there exist i[ n ] such that a+i1<min D ¯ <max D ¯ <a+i+r .

Case 1. If D ¯ [ n ]\ D ¯ , then D ¯ ={ 1,,r } , so that

α=( 1 r1 A r A r+1 A p 1 r1 r r+1 p ),

where r=min A r . Thus, define γ as

( 1 r1 r p1 { p,,n } 1 r1 r p1 p ).

Obviously, γFixOCT( [ n ],D ) and clearly γ 2 =γ .

Case 2. If [ n ]\ D ¯ D ¯ , then D ¯ ={ nr+1,nr+2,,n } so that α is of the form

( A 1 A nr+1 nr+2 n np+1 nr+1 nr+2 n ),

where nr+1=max A nr+1 . So, define

γ=( { 1,,np+1 } np+2 n np+1 np+2 n ).

Clearly, γE( FixOCT( [ n ],D ) ) .

Case 3. If 1<minD and maxD<n . Then, define

γ=( { 1,,a+1 } a+2 a+p1 { a+p,,n } a+1 a+2 a+p1 a+p ).

The element γ is clearly in E( FixOCT( [ n ],D ) ) . Hence, in all the three cases Imα=Imγ and by Theorem 2.14, ( α,γ ) , as such γ α , as required. □

Theorem 2.19. For n4 , the monoid FixOCT( [ n ],D ) is not right abundant.

Proof. If αFixOCT( [ n ],D ) , then obviously by Lemma 2.4, α ={ α } . □

The next lemma shows that the collection of idempotents in FixOCT( [ n ],D ) is a subsemigroup of FixOCT( [ n ],D ) .

Lemma 2.20. E( FixOCT( [ n ],D ) ) is a semilattice.

Proof. The proof is the same as the proof of (11], Theorem 7). □

Consequently, we have proved the following theorem.

Theorem 2.21. The monoid FixOCT( [ n ],D ) is left adequate.

3. The Combinatorial and Rank Properties of FixOCT( [ n ],D )

In this section, we determine the cardinality and rank of the monoid FixOCT( [ n ],D ) . These properties heavily depend on the size of the subset D , as we shall see below.

We now present the following proposition, which counts the number of elements each of height p in FixOCT( [ n ],D ) .

Proposition 3.1. Let D[ n ] such that | D ¯ |=r , and let F( n,p ) be as defined in (6). Then, for 1rpn

F( n,p )=( nr pr ).

Proof. To count the number of elements of height p in FixOCT( [ n ],D ) , first is to partition the set [ n ]\ D ¯ (which obviously has nr elements since | D ¯ |=r ) into pr parts (since the rank of each of the elements is p ). This is equivalent to selecting pr elements out of nr elements. The result now follows. □

Theorem 3.2. Let D={ i,,i+r1 }[ n ] such that | D ¯ |=r (1r<n) . Then

| FixOCT( [ n ],D ) |= 2 nr

Proof. Using Proposition 3.1, we see that

| FixOCT( [ n ], D ) |= p=r nr F( n,p )= p=r nr ( nr pr ) = p=r nr ( ( i1 )+n( i+r1 ) pr ) = 2 nr .

Rank of FixOCT( [ n ],D )

The semigroup S{ FixOCT( [ n ],D ), D n ( p ),L( nr,p ) } is J -trivial (from Corollary 2.6 and Theorem 2.7) and therefore, in line with [26], it admits a minimum generating set. Now, let J p * be defined as in (5). The next result shows that the collection of all the elements in J p * is the minimum generating set of D n ( p ) .

Lemma 3.3. Let α,β D n ( p ) . Then, αβ J p * if and only if α,β J p * and αβ=α .

Proof. Let α,β D n ( p ) and suppose αβ J p * . Thus, h( α )=h( β )=p , as such α,β J p * . Moreover, h( αβ )=p implies Imα is one of the transversals of kerβ and kerαβ=kerα . Thus, by Lemma 2.4 we have αβ=α .

The converse is obvious. □

From Proposition 3.1, we record the following remark:

Remark 3.4. For each rpn1 , | J p * |=( nr pr ) .

We now present the following theorem:

Theorem 3.5. Let D n ( p ) be as defined in (7). Then, the rank of D n ( p ) is given by:

rank( D n ( p ) )=( nr pr ).

Proof. Notice that J p * is the minimum generating set, as stated by Lemma 3.3, and it’s order is given by Remark 3.4. □

The following lemma plays a crucial role in determining the rank of L( nr,p ) .

Lemma 3.6. If α J p * then α J p+1 * for ( 1rpn2 ) .

Proof. Let α J p * be as expressed in (10). Now since pn2 , it means that there exists A k Kerα for some k{ 1,,i,i+r1,,p } such that a+k A k is a fixed point of α , i.e., ( a+k )α=( a+k ) . Now either ( a+k )=min A k or a+k=max A k or min A k <a+k<max A k . We consider the following cases:

Case 1: If a+k=min A k . Then, max D ¯ a+k . We may without loss of generality suppose D ¯ ={ a+i,,a+i+r1 } , where i+r1k . If i+r1=k , then α is of the form

( A 1 A i1 { min A i ,,a+i } a+i+1 a+k1 { a+k,,max A k } A k+1 A p a+1 a+i1 a+i a+i+1 a+k1 a+k a+k+1 a+p ).

In this case, define

β=( A 1 A i1 { min A i ,,a+i } a+i+1 a+k1 a+k { a+k+1,,max A k } A k+1 A p a+1 a+i1 a+i a+i+1 a+k1 a+k a+k+1 a+k+2 a+p+1 )

and

γ=( a+1 a+i1 a+i a+i+1 a+k1 { a+k,a+k+1 } a+k+2 a+p+1 { a+p+2,,n } a+1 a+i1 a+i a+i+1 a+k1 a+k a+k+1 a+p a+p+1 ).

Now if i+r1<k . Then, α has the form

( A 1 A i1 { min A i ,,a+i } a+i+1 a+i+r1 a+i+r a+k1 { a+k,,max A k } A k+1 A p a+1 a+i1 a+i a+i+1 a+i+r1 a+i+r a+k1 a+k a+k+1 a+p ),

and so β and γ are defined as

( A 1 A i1 { min A i ,,a+i } a+i+1 a+i+r a+k { a+k+1,,max A k } A k+1 A p a+1 a+i1 a+i a+i+1 a+i+r a+k a+k+1 a+k+2 a+p+1 )

and

( a+1 a+i a+i+r a+k1 { a+k,a+k+1 } a+k+2 a+p+1 { a+p+2,,n } a+1 a+i a+i+r a+k1 a+k a+k+1 a+p a+p+1 ),

respectively.

Case 2. If a+k=max A k . Then, a+kmin D ¯ . We may without loss of generality suppose D ¯ ={ a+i,,a+i+r1 } , where a+ka+i . If a+i=a+k then α is of the form

( A 1 A k1 { min A k ,,a+k } a+k+1 a+k+r1 A p a+1 a+k1 a+k a+k+1 a+k+r1 a+p ).

Now, define

β=( A 1 A k1 { min A k ,,a+k1 } a+k a+k+r1 A p a a+k2 a+k1 a+k a+k+r1 a+p ),

and

γ=( { 1,,a } a+k2 { a+k1,a+k } a+k+1 a+k+r1 a+p { a+p+1,,n } a+1 a+k1 a+k a+k+1 a+k+r1 a+p a+p+1 ).

If a+k<a+i and | A i |2 (in this case D ¯ ={ a+i } ), then α has the form

( A 1 A k1 { min A k ,,a+k } a+k+1 a+i1 { a+i,,max A i } A i+1 A p a+1 a+k1 a+k a+k+1 a+i1 a+i a+i+1 a+p ).

and so β and γ are defined as

( A 1 A k1 { min A k ,,a+k1 } a+k a+i1 { a+i,,max A i } A i+1 A p a a+k2 a+k1 a+k a+i1 a+i a+i+1 a+p )

and

( { 1,,a } a+k2 { a+k1,a+k } a+k+1 a+i a+p { a+p+1,,n } a+1 a+k1 a+k a+k+1 a+i a+p a+p+1 ),

respectively.

Also, if a+k<a+i and A i ={ a+i } , then α is of the form:

( A 1 A k1 { min A k ,,a+k } a+k+1 a+i a+i+r2 { a+i+r1,,max A i+r1 } A i+r A p a+1 a+k1 a+k a+k+1 a+i a+i+r2 a+i+r1 a+i+r a+p ).

Define β and γ as

( A 1 A k1 { min A k ,,a+k1 } a+k a+i1 a+i a+i+r2 { a+i+r1,,max A i+r1 } A i+r A p a a+k2 a+k1 a+k a+i1 a+i a+i+r2 a+i+r1 a+i+r a+p )

and

( { 1,,a } a+k2 { a+k1,a+k } a+k+1 a+i a+p { a+p+1,,n } a+1 a+k1 a+k a+k+1 a+i a+p a+p+1 ),

respectively.

Case 3: If min A k <a+k<max A k , then D must be singleton { a+k } . Thus, α is of the form

( A 1 A k1 { min A k ,,a+k,,max A k } A k+1 A p a+1 a+k1 a+k a+k+1 a+p ).

Now, define β and γ as

( A 1 A k1 { min A k ,,a+k } { a+k+1,,max A k } A k+1 A p a+1 a+k1 a+k a+k+1 a+k+2 a+p+1 )

and

( { 1,,a+1 } a+k1 { a+k,a+k+1 } a+k+2 a+p a+p+1 { a+p+2,,n } a+1 a+k1 a+k a+k+1 a+p1 a+p a+p+1 ).

Now, clearly in each case, β,γ J p+1 and also, βγ=α . The proof is now complete. □

Consequently, we obtain the rank of the two-sided ideal L( nr,p ) as stated in the following result:

Theorem 3.7. Let L( nr,p ) be as defined in (4), and let D n ( p ) be as defined in (7). Then, the rank( L( nr,p ) )=( nr pr ) .

Proof. The result follows from Lemma 3.6, Theorem 3.5 and Lemma 3.3. □

Next, we deduce the following result.

Corollary 3.8. Let D[ n ] such that | D ¯ |=r , and FixOCT( [ n ],D ) be as expressed in equation (3). Then, rank( FixOCT( [ n ],D ) )=nr+1 .

Proof. The result follows from Theorem 3.7 and the fact that rank( FixOCT( [ n ],D ) )=rank( L( nr,n1 ) )+| id [ n ] |.

We conclude the paper with the following isomorphism result:

Theorem 3.9. Let D 1 and D 2 be nonempty subsets of [ n ] . Then,

FixOCT( [ n ], D 1 )FixOCT( [ n ], D 2 )

if and only if D ¯ 1 = D ¯ 2 .

Proof. The result follows easily from Lemma 1.7.

Acknowledgements

The authors would like to thank Prof. Abdullahi Umar for technical and financial support.

Conflicts of Interest

The authors declare no conflicts of interest regarding the publication of this paper.

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