Quasilinear Degenerated Elliptic Systems with Weighted in Divergence Form with Weak Monotonicity with General Data ()
1. Introduction
In this paper, the main point is that we do not require monotonicity in the strict monotonicity of a typical Leray-Lions operator as it is usually assumed in previous papers. The aims of this text are to prove analogous existence results under relaxed monotonicity, in particular under strict quasi-monotonicity. The main technical tool we advocate and use throughout the proof is Young measures. By applying a Galerkin schema, we obtain easily an approximating sequence
. The Ball theorem [1] and especially the resulting tool mode available by Hungerbühler to partial differential equation theory give them a sufficient control on the gradient approximating sequence
to pass to the limit. This method is used by Dolzmann [2], G. J. Minty [3], H. Brezis [4], H. E. Stromberg [5], Muller [6], J. L. Lions [7], Kristznsen, J. Lower [8], M. I. Visik [9] and mainly by Hungurbühler to get the existence of a weak solution for the quasi-linear elliptic system [10]. This paper can be seen as generalization of Hungurbühler and as a continuation of Y-Akdim [11].
This kind of problems finds its applications in the model of Thomas-Fermis in atomic physics [12], and also porous flow modeling in reservoir [13].
2. Priliminaries
Let
the weight function systems defined in
and satisfying the following integrability conditions:
(2.1)
with
,
with
and which satisfies some hypotheses (see below).
We denote by
the real vector space of
matrices equipped with
the inner product
.
The Jacobian matrix of a function
is denoted by
with
.
The space
is the set of functions
with
The weighted space
can be equipped by the norm:
where
and
. the norm
is equivalent to the norm
, on
, such that,
.
Proposition 2.1 The weighted Sobolev space
is a Banach space, separable and reflexive. The weighted Sobolev space
is the closure of
in
equipped by the norm
.
Proof: The prove of proposition is a slight modification of the analogous one in [14] [Kufner-Drabek].
Definition 2.1 A Young measure
is called
-gradient young measures (
) if it is associated to a sequence of gradients
such that
is bounded in
. The
-gradient young measures
is called homogeneous, if it doesn’t depend on x, i-e, if
for a.e.
.
Theorem 2.1 (Kinder Lehirer-Pedregal) let
, be a family of probability measures in
. Then,
is
Young measures if and only if:
1) There is a
such that
, a.e in
.
2) Jensen’s inequality:
hold for all
quasi-convex, and.
3) The function:
. Here,
denotes the (not separable) space:
.
proof: see [15].
Theorem 2.2 (Ball) Let
be Lebesgue measurable, let
be closed, and let
, be a sequence of Lebesgue measurable functions satisfying
, as
, i.e. given any open neighborhood U of
,
. Then there existsa subsequence
of
and a family
, of positive measures on
, depending measurablyon x, such that
1)
, for a.e
.
2)
for a.e
.
3)
in
for each continuous functions
satisfying
[1].
Theorem 2.3 (vitali) Let
be an open bounded domain and let
be a sequence in
with
.
Then
is a cauchy sequence in the
-norm if and only if the two following conditions hold:
1)
is cauchy in measure (i.e.
,
as
.
2)
is equiintegrable i.e.:
(
and
such that
for all n whenever
and
). Note that if
converges pointiest, then
is cauchy in measure.
Hypotheses (H0) (Hardy-Type inequalities): There exist some constant
, some weighted function
and some real q (
) such that,
for all
, with
.
The injection
↪↪
is compact, and
↪↪
is compact, (by [14] ) with
(H1) Continuity:
is a Carathéodory function (i-e
is measurable for every
and
is continuous for almost every
). (H2) Growths and coercivity conditions: There exist
,
,
,
,
,
,
and
such that for all
,
, we have:
(2.2)
and
(2.3)
(H3) Monotonicity conditions:
satisfies one of the following conditions:
1) For all
, and all
, the map
is a
-function and is monotone (i-e,
, for all
, all
and all
).
2) There exists a function
such that
and
is convex and
function.
3) For all
, and for all
the map
is strictly monotone (i.e.,
is monotone and:
).
4)
is strictly p-quasi-monotone in F, i.e.,
for all homogeneous
-gradient young measures
with center of mass
which are not a single Dirac mass.
The main point is that we do not require strict monotonicity or monotonicity in the variables
in (H3) as it is usually assumed in previous work (see [15] or [16] ).
: (continuity)
is a Carathéodory function i-e:
is measurable for every
, and
,
is continuous for almost every
.
: (growth condition): The exist:
,
,
such that:
: (continuity) the map
is a Carathéodory function.
: (growth condition) There exist:
For all
and
.
Our aim of this paper is to prove the existence of the problem
in the space
.
Remark 2.1 -The condition
and
ensure the measurability of f and g for all measurable function u.
-
and
ensure that growths conditions, in particularly: if
then
and
is in
.
- Exploiting the convergence in measure of the gradients of the approximating solutions, we will prove the following theorem.
Theorem 2.4 If
and
satisfies the conditions (H0)-(H3), then the Dirichlet problem
has a weak solution
, for every
, f satisfies
and
and g satisfies
and
.
In order to prove theorems, we will apply a Galerkin scheme, with this aim in view, we establish in the following subsections, the key ingredient to pass to the limit for this, we assume that the conditions: (H0)-(H3),
,
,
and
.
Lemma 2.1 For arbitrary
and
, the functional
is well defined, linear and bounded.
Proof For all
, we denote
with
and
We define
Firstly, by virtue of the growth conditions (H2) and the Hölder inequality, one has
with
, and thanks to Hardy inequality we have:
with
. Which gives
and
We denote
.
Hence
. With
.
Finally the functional
is bounded.
Lemma 2.2 The restriction of F to a finite dimensional linear subspace V of
is continuous.
Proof Let d be the dimension of V and
a basis of V. Let
be a sequence in V which converges to
in V. The sequence
converge to
, so
and
a.e., on the other hand
and
are bounded by a constant c. Thus, it follows by the continuity conditions (H1), that
for all
and a.e. in
. Let
be a measurable subset of
and let
.
Thanks to the condition (H2), we get
By the continuity conditions
and
we have:
And
almost everywhere. Moreover we infer from the growth conditions
and
that the sequences:
,
and
Are equi-integrable. Indeed, if
is a measurable subset and
then:
(by
and Hölder inequality).
(by
and Hölder inequality).
(by Hölder inequality).
which implies that
is equi-integrable. And by applying the Vitali’s theorem, it follows that
for all
.
Finally
which means that
Remark 2.2 Now, the problem
is equivalent to find a solution
such that
, for all
.
In order tofind such a solution we apply a Galerkin scheme.
3. Galerkin Approximation
Remark 3.1 (Galerkin Schema)
Let
be a sequence of finite dimensional subspaces with
dense in
. The sequence
exists since
is separable.
Let us fix some k, we assume that
has a dimension d and that
is a basis of
. Then, we define the map,
Proposition 3.1 The map G is continuous and
tends to infinity when
tends to infinity.
Proof. Since F restricted to
is continuous by Lemma 2.2, so G is continuous.
Let
and
in
, then
and which implies that
tends to infinity if
tends to infinity.
and
which implies that
tends to infinity if
tends to infinity.
Now, it suffices to prove that
Indeed, thanks to the first coercivity condition and the Hölder inequality, we obtain
By the Hölder inequality, we have
where
is a constant positive. For
large enough, we can write
And since
Finally, it follows from the growth condition
and
that:
with
is a constant. With;
and
, we get:
(3.1)
Consequently, by using (3.1), we deduce
and
Remark 3.2 The properties of G allow us to construct our Galerkin approximations.
Corollary 3.1 For all
, there exists
such that
, for all
.
Proof By the proposition 3.1, there exists
, such that for all
, we have
. And the usual topological argument see [Zei 86 proposition 2.8] [17] implies that
has a solution
. So, for all
, there exists
, such that
Taking
, so we obtain:
Proposition 3.2 The Galerkin approximations sequence constructed in corollary (3.1) is uniformly bounded in
; i.e.,
There exists a constant
, such that
, for all
.
Proof Like in the proof of proposition (3.1), we can see that
Then, there exists R satisfying
when
. Now, for the sequence of Galerkin approximations
of corollary (3.1), which satisfying
, we have the uniform bound
, for all
.
Remark 3.3 There exists a subsequence
of the sequence
, such that:
in
and
in measure in
;
with
The gradient sequence
generates the young measure
. Since
in measure, then
generates the Young measure
, see [2]. Moreover, for almost x in
, we have,
1)
is the probability measure, i.e.,
.
2)
is the
gradient homogeneous young measure.
3)
, see [18].
Proof. See [2]. (Dolzmann, N. Humgerbuhler S. Muller, Non linear elliptic system …)
4. Passage to the Limit
Now, we are in a position to prove our main result under convenient hypotheses.
Let
(4.1)
Lemma 4.1 (Fatou lemma type)(See [2] ) Let:
be a Carathéodory function, and
a measurable sequence, such that
generates the Young measure
, with
, for a.e.
. Then:
(4.2)
which provided that the negative part of
is equi-integrable.
Proof.
Lemma 4.2 Let
and
be a sequence which is uniformly bounded in
. There exists a subsequence of
(for convenience not relabeled) and a function
such that
in
And such that
in measure on
and in
, with:
Proof. see [10].
Lemma 4.3 The sequence
is equi-integrable.
Proof
We have
(4.3)
We denote
. Thanks to the coercivity condition (H2), we have
(4.4)
with
. Therefore,
for all
.
Similarly for
.
Now, by using the growth condition (H2) and the Hardy inequality (H0), we have
(4.5)
Thus, by the Hölder inequality, we obtain
(4.6)
So, by combining (4.5) and (4.6), we deduce that
(4.7)
Similarly to
, we obtain
. Finally:
is equi-integrable.
We choose a sequence
such that
belongs to the same space
and
in
, this allows us in particular, to use
as a test function in (3.1). We have:
(4.8)
The first term on the right in 4.8 converge to zero since
in
. By the choice of
, the sequence
uniformly bounded in
, and lemma (4.2). Next, for the second term:
in 4.8 it follows from the growth condition
and the Hölder inequality that:
By the equivalence of the norm in
and the sequence
is uniformly bounded in
,
is bounded.
Moreover, by the construction of
, and lemma (4.2) we have:
We infer that the second term in 4.8 vanishes as
. Finally, for the last term
in 4.8, we note that
Strongly in
by
,
and lemma (4.2).
Indeed we may assure that
almost everywhere.
,
and
Now, we consider
. We have,
is equi-integrable because
it is. So, we define
So to prove (??), it suffices to prove that:
(4.9)
Let
, so there exists
such that, for all
, we have
since:
,
Or in an equivalent manner
,
then for all
, we have
Combining (H2) and (0.1), we get
For all
, we choose
such that
(4.10)
For all
, which implies that
Hence
. According to Hölder and Hardy inequalities, and by (4.1) we deduce that
Therefore,
which proves that
, and finally
Proof of theorem:
For arbitrary
in
. It follows from the continuity condition
and
that
and
almost everywhere. Since, by the growth conditions
,
and the uniform bound of
,
and
are equi-integrable, it follows that the Vitali’s theorem. This implies that:
for all
and
for all
We will start with the easiest case
(d):
is strict p-quasi-monotone. (4.11)
Indeed, we assume that
is not a Dirac mass on the set M with
of positive Lebesgue measure
. Moreover, by the strict p-quasi-monotonicity of
and
is an homogeneous
gradient young measure for a.e.
. So, for a.e.
, with
, with
is the differentiable approximation in x. We get
On the other hand (4.9), integrating over
, and using the div-cul inequality we have:
Which is a contradiction with (3.8). Thus
for a.e.
. Therefore,
in measure when k tends to infinity. Then, we get
for all
. In the other hand, for all
;
a.e.
. Moveover, for all
measurable, it is easy to see that:
because
. And thanks to Vitali’s theorem, we obtain:
, for all
.
which proves the theorem in this case.
Remark 4.1 Before treating the cases (a),(b) and (c) of (H3), we note that
(4.12)
Since
thanks to the div-Curl inequality in (4.9). On the other hand, the integrand in (4.12) is non negative, by the monotonicity of
. Consequently, the integrating should be null, a.e., with respect to the product measure
, which mean
(4.13)
Thus,
(4.14)
Case c: We prove that, the map
is strictly monotone, for all
and for all
.
Sine
is strict monotone, and according to (4.14),
which implies that,
in measure. For the rest of our prove is similarly to case d.
Case b: We start by showing that for almost all
, the support of
is contained in the set where W agrees with the supporting hyper-plane.
So, it suffices to prove that
(4.15)
If
, thanks to (4.14), we have
(4.16)
On the other hand, since
is monotone, for all
we have:
(4.17)
By subtracting (4.16) from (4.17), we get
(4.18)
for all
. Doing the same by the monotonicity in (4.18), we obtain
(4.19)
Combining (4.18) and (4.19), we conclude that
(4.20)
for all
, and for all
.
Now, it follows from (4.19) that
Witch prove (4.15).
Now, by the coercivity of W, we get
for all
. Therefore,
L is a supporting hyper-plane, for all
. (4.21)
Moveover, the mapping
is continuously differentiable, so we obtain
(4.22)
Thus,
(4.23)
Now, we consider the Carathéodory function
and lets
is equi-integrable. Thus, thanks to BALL’s theorem, see [6]
weakly in
, and the weakly limit of g is given by
According to (4.22) and (4.23), and since
, it follow that
strongly in
by Fatou lemma, which gives
Thus
This completes the proof of the case (b).
Case (a): In this case, on
, we affirm that,
(4.24)
for all
, where
is the derivative with respect to the third variable of
and
.
Thanks to the monotonicity of
, we have
By invoking (4.19), we obtain
On the other hand,
is a
function, so
Thus
which gives
t is arbitrary in (4.24).
Finally for all
the sequence
is equi-integrable. Then, by the BALL’s theorem, see [1] the weak limit is
By choosing
in (4.24), we obtain
Hence:
This proves that
And since
is dense in
, so u is a weak solution of
, as desired.
Remark 4.2 In case (b)
strongly, but in the case (c) and (d)
in measure.
Exemple 4.1 We shall suppose that the weight functions satisfy:
for some
; and
, with
, for all
,
, and
with
a.e in
then, we can consider the Hardy inequality in the form:
for every
with a constant
independent of u and for some
. Let us consider the Carathéodory functions:
The above functions defined by
satisfies the growth conditions (H2).
In particular, let use the special weight function
expressed in term of the distance to the boundary
denote
and
,
the hardy inequality reads:
and the corresponding
↪
is compact if:
1) For,
2) For,
3) For,
, by the simple modifications of the example in [11]. Moreover, the monotonicity condition are satisfied:
for almost all
and for all,
. This last inequality cannot be strict, since for
with
for all
. But
for
,
,
the corresponding expression is Zero.